Bit wise | OR operation in C++: Explained with program and Truth table.

Overview:

The | (bitwise OR) in C or C++ takes two numbers as operands and does OR on every bit of two numbers. The result of OR is 1 if any of the two bits is 1.

| - bitwise OR :

OR gate:

Truth table :

INPUT 1	INPUT 2	OUTPUT
A	B	A+B
0	0	0
0	1	1
1	0	1
1	1	1

Sample C++ program using : OR gate :

 

Example 1: 

 

#include <iostream>

#include<stdio.h>

int a=5; //binary = 0101

int b=12; //binary =1100

int main() {

std::cout << (a|b); //output will be=13 binary --> 1101

return 0;

}

 

 

Example 2:

 

#include <iostream>

using namespace std;

int main() {

 

int a = 5;// 0101b

 

int b = 12;// 1100b

 

int c = a | b; // 1101b

 

std::cout << "a = " << a << ", b = " << b << ", c = " << c << std::endl;

 

return 0;

}

When the binary value for a ( 0101 ) and the binary value for b ( 1100 ) are OR 'ed together we get the binary value of
1101 :
int a = 0 1 0 1
int b = 1 1 0 0
---------
int c = 1 1 0 1

Decimal to Binary conversion :

 

Step 1: Divide the given decimal number by 2 and note down the remainder.
Step 2: Now, divide the obtained quotient by 2, and note the remainder again.
Step 3: Repeat the above steps until you get 0 as the quotient.
Step 4: Now, write the remainders in such a way that the last remainder is written first, followed by the rest in the reverse order.

 

Example :

Lets take the decimal number 13 :

 

 13÷2 = 6 ---> Reminder ---> 1

 6÷2   = 3 ---> Reminder ---> 0

 3÷2   = 1 ---> Reminder ---> 1

 1÷2   = 0 ---> Reminder ---> 1

 

13 in binary = 1101

 

 

Binary to Decimal conversion :

Converting number : 11000100 

  =196

Decimal to Binary Table :

 

Decimal Numbers	Binary Numbers
0	0
1	1
2	10
3	11
4	100
5	101
6	110
7	111
8	1000
9	1001
10	1010
11	1011
12	1100
13	1101
14	1110
15	1111